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k Al false&cld; 3458948&centerwin; yes C https:// www.mathxl.com/Student/PlayerHomework.aspx?homeworkld-328167003&questionld-4;&flushed; Amer Alharbi 0/30/15 1:45 PM Homework: Homework #17 Statistics Histogram Overview Instructor-created question 9 of 10 complete Exercise Score: 0 of 4 pts Assignment Score: 86.97% (40.88 of 47 pts) One of the NAE Grand Challenges for Engineering is Develop Carbon Sequestration Methods. Examine the increase in monthly co2 emissions for 2009, taken from the Mauna Loa data set. All values given are in parts per million [ppm] CO2 as the difference between the December 2008 and the monthly 2009 reading. I? Click the icon to view the information about the carbon sequestration Methods and the Keeling curve Click the icon to view the graph Click the icon to view the table of the increase in monthly CO2 emissions for 2009 Data Table (a) What is the mean of these data 1.38 4.64 0.77 3.23 2.20 0.45 The mean of the data is ppm. (Round your answer to three significant dig 1.87 3.89 6 3.92 0.37 73 Print Done (b) What is the median of these data? The median of the data is 1.80 ppm. (Round your answer to three significant digits.) (c0 The variance of the data set shown here is 3.5 parts per million squared [ppm2]. What is the standard deviation of these data? The standard deviation of these data is ppm. Round your answer to three significant dig (d) The estimated annual growth rates for Mauna Loa are close, but not identical, to the global growth rates. The standard deviation of the differences is 0.26 parts per million per year [ppm/year]. What is the variance? The variance of the differences is [ppm/year (Round your answer to three significant dig th k Check A Check Answer All part Clear All Save

Solution

a) mean = (1.38 + 4.64 - 0.77 + 3.23 + 2.2 + 0.45 + 1.89 + 3.89 - 1.16 + 3.92 + 0.37 + 1.73)/12 = 1.8125

b)Median:

arranging in ascending order: -1.16 , -0.77, 0.37, 0.45, 1.38, 1.73, 1.89, 2.2, 3.23, 3.89, 3.92, 4.64

n= 12, even

so median = (1 + (n/2))th item = 1 + (12/2) th item = 7th item = 1.89

c) variance = 3.5

    standard deviation = variance^0.5 = 3.5^0.5 = 1.87

d) variance = standard deviation^2 = (0.26)^2 = 0.0676

 k Al false&cld; 3458948&centerwin; yes C https:// www.mathxl.com/Student/PlayerHomework.aspx?homeworkld-328167003&questionld-4;&flushed; Amer A

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