The math club sells candy bars and drinks during football ga

The math club sells candy bars and drinks during football games. 60 candy bars and 110 drinks will sell for dollar 265. 120 candy bars and 90 drinks will sell for dollar270. How much does each candy bar sell for? (Note: Express the answer In dollars.cents.)

Solution

Given that

60 candy bars and 110 drinks will sell for $265

120 candy bars and 90 drinks will sell for $270

Let Candy bars = C , Drinks = D

Then

We are forming equations for given data

60C + 110D = $265

i.e 12C + 22D = $53

12C = $53 - 22D ............................. 1

120C + 90D = $270

i.e 12C + 9D = $27

12C = $27 - 9D ................................. 2

Solving equation 1 and 2

We know that if left hand side of equations are equal then equating right hand side of both equations

Hence,

$53 - 22D =  $27 - 9D

$53 - $27 = -9D + 22D

$26 = 13D

D = $26 / 13

D = $2

Substitute D = 2 in equation 1

12C = $53 - 22D

C =  ($53 - 22D )/ $2

C = ( $53 - (22 x$2)) / 12

C = ( $53 - $44) / 12

C = $9 / 12

C =$0.75

Therefore,

Each candy bar cost = $0.75