Question 2 Follow Link below httpimgurcomY9aBgNNSolutionLet

Question 2: Follow Link below

http://imgur.com/Y9aBgNN

Solution

Let F be the Force of attraction between the two charges

                                                                      F = k q1 * q2 / r^2

                                                                         = 8.98 * 10^9 * - 2.93 *10^-6 * 6.91 * 10^-6 / (0.0434)^2

                                                                         = -96.525 N , the foce is attractive.

the magnitude of force that once exerts on other is the same which is 96.525 N , which is newtons 3rd law.

2 . let the new particles with identical charge be q , if the new particles carry same charge then net force of replusion

                                     F = k . q ^ 2 / r ^2 = 96.525

                                        8.98 * 10^9 * q ^2 / (0.0434 )^2 = 96.525

                                                                    q = sqrt {(96.525 * 0.0434 ^2) / (8.98 * 10^9 )}

                                              q = 4.499 * 10^-6