You are working on Hardey Weinberg equations and the above t

You are working on Hardey Weinberg equations, and the above table shows allele frequencies for certain populations.

In population 6, the a allele is detrimental, and the A allele is incompletely dominant such that AA is relatively the fittest, Aa has a fitness of 0.8, and aa has a fitness of 0.6. If there is no mutation, what will p and q be in the next generation? Show all steps and explain.

Population AA Aa aa 1.0 0.0 0.0 1.0 0.0 0.0 1.0 0.0 0.0 4 0.25 0.25 0.5 5 0.25 0.25 0.5 6 0.25 0.25 0.5 7 0.33 0.33 0.33 8 0.64 0.04 0.32 9 0.64 0.32 0.04 10 0.986049 0.013902 0.000049

Solution

If the proportion of genotypes are:

So according to hardy weinberg equation p² + 2pq + q²

so allellic frequency of p is 0.5 and the frequency of q is 0.5

= 0.25+2* (0.5)(0.5) +0.25 = 1

So the The probability of an A sperm meeting an A egg is 0.5 x 0.5 = 0.25. The probability of an A sperm meeting an a egg is 0.5 x 0.5 = 0.25. The probability of an a sperm meeting an A egg is 0.5 x 0.5 = 0.25 The probability of an a sperm meeting an a egg is 0.25 x 0.25 = 0.25

That is, if there were a thousand offspring, there would be:

In the next generation also the allelic frequency of p and q is 0.5