A mass M 10 kg rests on a horizontal rough surface is attac

Solution

a).

Write the equation for the friction force acting on the mass M

f_s = mg

Where is coefficient of friction and m is the mass and g is the gravitational acceleration

Substitute = 0.5 , m = 1.0 kg and g = 10 m/s²

f_s = (0.5)(1.0 kg)(10 m/s² )

= 5 N Answer

b).

Write the equation for the maximum value of F_x

F_x = k_A*x

Substitute k_A = 100 N/m and x = 0.03 m

F_x =(100 N/m)*(0.03 m)

= 3 N Answer

c).

Write the equation for the maximum value of F_Y

F_Y = k_By + mg - f_s

Substitute k_B = 100 N/m, y = 0.04 m, m = 1.0 kg and g = 10 m/s² and f_s = 5 N

F_Y = (100 N/m)(0.04 m) + (1.0 kg)(10 m/s²) - 5 N

= 9 N Answer

d).

Write the equation for the work done by the F_x in Joules

W_x = F_x *x

Substitute F_x = 3 N and x = 0.03 m

W_x = (3 N)*(0.03 m)

= 0.09 Joules Answer

e).

Write the equation for the work done by the F_y in Joules

W_y = F_y *y

Substitute F_y = 9 N and y = 0.04 m

W_x = (9 N)*(0.04 m)

= 0.36 Joules Answer