I ONLY NEED THE ANSWER TO PART B ThanksSolutionp107 p205 p30

I ONLY NEED THE ANSWER TO PART B!!! Thanks

Solution

p1=0.7; p2=0.5; p3=0.6; p4=0.9; p5=0.2

q1=0.3; q2=0.5; q3=0.4; q4=0.1; q5=0.8 where qi=1-pi.

now probability of flow of current from A to B = 1- probability of no current flowing from A to B

so, probability of no current flowing from A to B = prob(1,2 are open) +prob(4,5 are open) + prob(1,3,5 open) + prob(2,3,4 open) = q1*q2 + q4*q5 +q1*q3*q5 + q2*q3*q4 = 0.346

so answer =1 -0.346 =0.654