please help me
Question 2 (poissan distribution, 15 points) f the customer arrival rate is 10 customers/10 mins, (a) what is the probability to have 2 customers in 45 minutes? (s points) (b) What is the probability to have at most customers in the 30 minutes? (5 points) 1 (c) For the question (a), what is mean and standard deviation? (5 points) Hints: To solve question regarding to poisson distribution, correctly determine A. Question (a) is single probability. Question (b) is cumulative probability, to solve it, break it into single probabilities. Related formulas: P(c) Mean Variance
a) 2.883x10-17
b) 2.8073x10-12
c) Mean = 45 and std dev = 6.708
Working notes: 1 customer per minute
Hence for 45 min lemda = 45
variance = mean = lemda = 45
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