Agnes has a weighted coin so that heads comes up 23 of the t

Agnes has a weighted coin so that heads comes up 2/3 of the time. She tosses her coin five

times. What is the probability that heads will appear for the rst time on toss 5?

Solution

Probability of getting a head, p = 2/3

Probability of getting a tail, (1-p) = 1/3

Now,

P ( getting H at the 1st draw ) = 2/3

P ( getting H at the 2nd draw ) = P (getting T at the 1st draw and H at the 2nd draw ) = 1/3 x 2/3 = 2/9

P ( getting H at the 3rd draw ) = P (getting T at the 1st and 2nd draw and H at the 3rd draw ) = 1/3 x 1/3 x 2/3 = 2/27

P ( getting H at the 4th draw ) = P (getting T at the 1st , 2nd and 3rd draw and H at the 4th draw ) = 1/3 x 1/3 x 1/3 x 2/3 = 2/81

P ( getting H at the 5th draw ) = P (getting T at the 1st , 2nd , 3rd and 4th draw and H at the 5th draw ) = 1/3 x 1/3 x 1/3 x 1/3 x 2/3 = 2/243

Agnes has a weighted coin so that heads comes up 2/3 of the time. She tosses her coin five times. What is the probability that heads will appear for the rst tim

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