A particular program say program A previously drew 30 of th
A particular program, say, program A, previously drew 30 % of the television audience. To determine if a recent rescheduling of the programs on a competing channel has adversely affected the audience of program A, a random sample of 400 viewers is to be asked whether or not they currently watch this program. If the percentage of viewers watching program A has not changed, what is the probability that fewer than 105 out of a sample of 400 will be found to watch the program? Round your answer to four decimal places.
Solution
We first get the z score for the critical value:          
           
 x = critical value =    104.5      
 u = mean = np =    120      
           
 s = standard deviation = sqrt(np(1-p)) =    9.16515139      
           
 Thus, the corresponding z score is          
           
 z = (x-u)/s =    -1.691188649      
           
 Thus, the left tailed area is          
           
 P(z <   -1.691188649   ) =    0.045400389 [ANSWER]

