asap due tonight by 1159 pm ty Barbara Fi Solutionfx 4x2 x

asap due tonight by 11:59 pm ty

Barbara Fi

f(x) = 4x^2 -x -3

a) Point ( 2,11)

To check whether (2, 11) lies on graph plug the points and check is satifies the equation

f(2) = 4*(2)^2 -2 -3

= 16 -5 =11

Yes point lies on the graph

b) Not clear .It seems f(x) =-3

So, -3 =4x^2 -x -3

4x^2 -x =0----> x( 4x-1)=0

x=0 ; x= 1/4

c) Domain of f(x) = 4x^2 -x -3 : All Real : ( -infinity , +infinity)

d) X intercept: 4x^2 -x-3 =0

4x^2 - 4x +3x -3 =0

4x( x-1) +3(x-1) =0

(4x+3) (x+3) =0

x= -3/4 x=-3 are the x intercepts

d) Y intercept: Plug x=0 we get f(x) = -3