Give the location of the vertical asymptotess if they exist

Give the location of the vertical asymptotes(s) if they exist, and state the function\'s domain.

h(x)= (x^2-1)/(2x^2+3x-5)

Solution: - h(x) = [(x² -1)/(2x² +3x -5)]

Domain: = {x belong to R; x is not equal to 1 & x is not equal to (-5/2)}

Vertical asymptote is x = (-5/2)

$Give the location of the vertical asymptotes(s) if they exist, and state the function\'s domain. h(x)= (x^2-1)/(2x^2+3x-5)SolutionSolution: - h(x) = [(x2 -1)/(2$

Give the location of the vertical asymptotess if they exist

Solution

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