Determine for which values of m the functions phix xm is a
Solution
y =x^m
y\'= mx^(m-1)
y\'\'=m(m-1)x^(m-2)
3x^2 y\'\' + 11xy\' -3y=0
3x^2(m)(m-1)x^(m-2) + 11xmx^(m-1) - 3x^m=0
3m(m-1)x^m+11mx^m-3x^m=0
taking out x^m
3m(m-1)+11m-3=0
3m^2-3m+11m-3=0
3m^2+8m-3=0
3m^2+9m-m-3=0
3m(m+3)-1(m+3)=0
(3m-1)(m+3)=0
m=1/5,-3
