Percentage of scores failing between a z of 173 and the mean

Percentage of scores failing between a z of -1.73 and the mean Percentage of scores failing below a z of 2.56 Percentage of scores failing below a z of -24 Percentage of scores failing above a z of 1.44 Percentage of scores failing above a z of -.67 Percentage of scores failing between z\'s of -80 and +.80 Percentage of scores failing between z\'s of -.53 and +.84

Solution

2.

z1 = lower z score =    -1.73      
z2 = upper z score =     0      
          
Using table/technology, the left tailed areas between these z scores is          
          
P(z < z1) =    0.041815138      
P(z < z2) =    0.5      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.458184862 = 45.82%   [ANSWER]

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3.

Using a table/technology, the left tailed area of this is          
          
P(z <   2.56   ) =    0.994766392 = 99.48% [ANSWER]

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4.

Using a table/technology, the left tailed area of this is          
          
P(z <   -0.24   ) =    0.405165128 = 40.52% [ANSWER]

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5.

Using a table/technology, the right tailed area of this is          
          
P(z >   1.44   ) =    0.0749337 = 7.493% [ANSWER]

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