For a lab report I am working on I must identify the critica

For a lab report I am working on I must identify the critical temperature of a superconductor. However, the data I have is in mV. If i know the mV that corresponds to the critical temperature, how do I convert from mV to kelvin? (using table below). More specifically, the values i need converted are 5.40 mV and 5.29 mV. Thanks!

Conversion from mV to Kelvin 6 60 7.60 7.53 7.46 7.40 7.33 726 7.19 7.12 7.05 6.99 6.92 60 70 6.92 6.85 6.78 6.716.64 6.56 6.49 642 6.37 6.33 6.29 70 80 6.29 6.25 6.21 6.17 6.13 6.09 6.05 6.015.97 5.93 5.9080 90 5.90 5.86 5.83 5.79 5.75 572 5.68 5.64 5.60 5.56 5.52 90 100 5.52 5.48 5.44 541 5.37 5.34 5.30 5.27 5.23 5.20 5.16 100 110 5.16 5.13 5.09 5.06 5.02 4.99 4.95 4.9 4.88 4.84 481 0 1204.81 4.77 4.74 4.70 467 4.63 4.60 4.56 4.53 449 4.46120 130 4.46 4.42 4.39 4.35 4.32 4.28 4.25 42.18 4.14 4.1130 140 4.14.07 4.04 4.00 3.97 3.93 3.90 3.86 3.83 3.79 3.76140 150 3.76 3.73 3.69 3.66 3.63 3.60 3.56 3.53 3.50 3.47 3.43 150 160 3.43 3.40 3.37 3.34 3.30 3.27 3.24 3.21 3.18 3.15 3.12 160 170 3.12 3.09 3.06 3.03 3.00 2.97 2.94 2.91 2.88 2.85 2.82 170 180 2.82 2.79 2.76 2.73 2.70 2.67 2.64 2.61 2.58 2.53 2.52 180 190 2.52 2.49 2.46 2.43 2.40 2.37 2.34 2.31 2.29 2.26 2.23190o 2002.23 2.20 2.17 24 2.1 2.08 2.05 2.02 1.99 196193 200 210 1.93 1.90 1.87 1.84 81 .78 1.75 .72 1.69 1.661.64 210 220 1.64 .61 59 .56 54.51 1.49 1.46 .44 41 1.39 220 230 1.39 36 134 1.31 .29 1.26 1.24 .19 1.161.14 230 240 1.14 .1 .09 107 04.02 0.99 0.97 0.94 0.92 0.89 240 250 0.89 0.87 0.84 0.82 0.79 0.77 0.74 0.72 o.69 0.67 0.65 250 260 0.65 0.62 0.60 0.58 055 0.53 0.50 0.48 0.45 0.42 0.40 260 270 0.40 0.38 0.36 0.34 0.32 0.30 0.28 0.26 0.24 0.22 0.20 270 2800.20 0.18 0.16 0.14 0.12 0.10 0.08 0.06 0.04 0.02 0.00 280 290 0.00 -0.02 -o.04 -0.060.08 0.10 -012 0.14 -0.16 0.18 -0.20 290 300 -0.20 -0.22 -0.24 -0.26 -0.28 -0.30 -0.32 -0.34 -0.36-0.38 -0.40 300

Solution

Step 1 First point out the electric potential (voltage), you want to be converted to K, in the chart.

Step 2 Let\'s say V = 5.40 mV. Then correlate it with its corresponding Kelvin value (temperature) in leftmost/rightmost vertical column. 5.40 mV corresponds to 100K.

Step 3 Then correlate the potential to the topmost horizontal row value. 5.40 mV corresponds to 3.

Step 4 Add it with temperature value obtained in step 2.

Therefore, 5.40 mV converted to temperature 103 K.

and, 5.29 mV converted to temperature 106 K.