Given an arithmetic sequence with a7 3 and a21 38 find a33
     Given an arithmetic sequence with a_7 = -3 and a_21 = -38, find a_33. a_33 =  (Simplify your answer.) 
  
  Solution
a7 = -3 ; a21 = -38
a7 = a1 + (n-1)d
-3 = a1 + 6d ----(1)
-38 = a1 + 20d ----(2)
-------------------------------- (subtract)
35 = -14d
d = -2
-3 = a1 + 6d --->a1 = -3 -6d = -3 -6(-2) = -3 +12 =9
a33 = a1+ (33-1)d = 9 + 32*(-2) = 9 -64 = -55
a33 = -55

