My volume of the ice that was formed was 0380 mL I divided t

My volume of the ice that was formed was 0.380 mL. I divided this by the volume change for ice to water at 0 degrees celicus and got a mass of 4.19 g. I am unsure of where to go from here. The heat of vaporizatio I am trying to find is for acetone.

Solution

Heat required to vaporize the water is equal to the sum of heat required to boil the water and vaporize the water. so

Q = m c ( T_f - T _i ) + m L_v

     = ( 4.19x10^-3 kg) [ ( 4813 J / kg. K ) ( 100 ) + (2260x10³ J / kg ) ]

     =11486 J