An assembly line produces widgets with a mean weight of 10 a
Solution
1.
Formulating the null and alternative hypotheses,              
               
 Ho:   sigma   >=   0.2  
 Ha:    sigma   <   0.2  
               
 As we can see, this is a    left   tailed test.      
               
 Thus, getting the critical chi^2, as alpha =    0.1   ,      
 alpha =    0.1          
 df = N - 1 =    19          
 chi^2 (crit) =    11.65091003        
               
 Getting the test statistic, as              
 s = sample standard deviation =    0.126          
 sigmao = hypothesized standard deviation =    0.2          
 n = sample size =    20          
               
               
 Thus, chi^2 = (N - 1)(s/sigmao)^2 =    7.5411          
               
 As chi^2 < chi^2(crit), then we REJECT THE NULL HYPOTHESIS.              
Thus, there is significant evidence that the new process is less variable than the old. [CONCLUSION]
*******************************************
Hi! Please submit the next part as a separate question. That way we can continue helping you! Please indicate which parts are not yet solved when you submit. Thanks!

