Consider the following probabilities PAc 064 PB 054 and PA

Consider the following probabilities: P(Ac) = 0.64, P(B) = 0.54, and P(A ? Bc) = 0.12.

a.	Find P(A | Bc). (Do not round intermediate calculations. Round your answer to 2 decimal places.)

P(A | Bc)

b.	Find P(Bc | A). (Do not round intermediate calculations. Round your answer to 3 decimal places.)

P(Bc | A)

c.	Are A and B independent events?
	Yes because P(A | Bc) = P(A). Yes because P(A ? Bc) ? 0. No because P(A | Bc) ? P(A). No because P(A ? Bc) ? 0.

Consider the following probabilities: P(Ac) = 0.64, P(B) = 0.54, and P(A ? Bc) = 0.12.

Solution

p(a)=1-0.64=0.36

a)0.12/0.46
b)0.12/0.36
c)a