Question 4 of 10 A package contains 9 resistors 3 of which a

Question 4 of 10 A package contains 9 resistors, 3 of which are defective. If 5 are selected, find the probability of getting the following results. Use a graphing calculator and round the answers to six decimal places. Part1 0 defective resistors. Part2 1 defective resistor. Part 3 3 defective resistors.

Solution

Given,

Total Resistors=9

Defective Resistors=3.

So Non-Defective Resistors=9-3=6

a) P(0 defective Resistor)

We needs to Choose from 6 Non Defective Resistors

P(0 defective Resistor)= 6C5/9C5= 6*5*4*3*2/9*8*7*6*5=720/15120=0.0476

b) P(1 defective Resistor)

We needs to Choose 1 Defective Resistors and 4 Non Defective Resistors

P(1 defective Resistor)= 3C1*6C4/9C5=

3C1*6C4=3*6*5*4*3/4*3*2*1=45

9C5=15120

P(1 defective Resistor)=45/15120=0.002976

c) P(3 defective Resistor)

We needs to Choose 3 Defective Resistors and 2 Non Defective Resistors

P(1 defective Resistor)= 3C3*6C2/9C5=

3C3*6C2=1*6*5/2*1=15

9C5=15120

P(1 defective Resistor)=15/15120=0.00099