For the numbers find the area between the mean and the z sco

For the numbers find the area between the mean and the z score z= 1.17 z=-1.37

Mean ( u ) =0
Standard Deviation ( sd )=1
Normal Distribution = Z= X- u / sd ~ N(0,1)
To find P(a < = Z < = b) = F(b) - F(a)
P(X < -1.37) = (-1.37-0)/1
= -1.37/1 = -1.37
= P ( Z <-1.37) From Standard Normal Table
= 0.08534
P(X < 1.17) = (1.17-0)/1
= 1.17/1 = 1.17
= P ( Z <1.17) From Standard Normal Table
= 0.879
P(-1.37 < X < 1.17) = 0.879-0.08534 = 0.7937