1 Write the polynomial as the product of linear factors fx
1) Write the polynomial as the product of linear factors.
f(x) = x2 + 81
f(x) =
List all the zeros of the function. (Enter your answers as a comma-separated list.)
x =
2) Write the polynomial as the product of linear factors.
h(x) = x2 6x + 18
h(x) =
List all the zeros of the function. (Enter your answers as a comma-separated list.)
x =
3)Write the polynomial as the product of linear factors.
f(x) = x4 16
f(x) =
List all the zeros of the function. (Enter your answers as a comma-separated list.)
x =
4) Write the polynomial as the product of linear factors.
f(z) = z2 10z + 26
f(z) =
List all the zeros of the function. (Enter your answers as a comma-separated list.)
z =
5) Write the polynomial as the product of linear factors.
h(x) = x3 x + 60
h(x) =
List all the zeros of the function. (Enter your answers as a comma-separated list.)
x =
6) Write the polynomial as the product of linear factors.
f(x) = 5x3 9x2 + 18x + 4
f(x) =
List all the zeros of the function. (Enter your answers as a comma-separated list.)
x =
7) Write the polynomial as the product of linear factors.
g(x) = x4 2x3 + 10x2 18x + 9
g(x) =
List all the zeros of the function. (Enter your answers as a comma-separated list.)
x =
Solution
1) f(x) =x^2 +81
= x^2 - (-9i)^2 ( a^2 - b^2 = (a+b)(a-b) )
= (x -9i)(x +9i)
There are no real zeros only imaginary roots are present:
(x -9i)(x +9i) =0
x = 9i ;x = -9i
2) h(x) = x^2 6x + 18
find the roots of polynomial by quadratic formula:
x = ( -b + /- sqrt(b^2 -4ac) )/2a
= ( 6 + / - sqrt(36 - 4*18) )/2 = ( 6 + / sqrt(-36) )/2
= 3 + /- i*3
= 3 +/ - 3i
So, h(x) = ( x-3 -3i)(x -3 +3i)
zeros are x = 3 +3i , 3-3i
3) f(x) = x4 16
Use the formula : (a^2 -b^2) = (a+b)(a-b)
x^4 -16 = (x^2 +4)(x^2 -4)
= (x +2i)(x-2i)(x+2)( x-2)
f(x) = (x +2i)(x-2i)(x+2)( x-2)
zeros : f(x)=0
(x +2i)(x-2i)(x+2)( x-2) =0
x = -2i , 2i , -2 , 2
4) f(z) = z^2 -10z +26
find the roots of polynomial by quadratic formula:
x = ( -b + /- sqrt(b^2 -4ac) )/2a
z = ( 10 + /- sqrt(100 -4*26) )/2
= ( 10 +/-2i)/2
= 5 +/- i
z = 5 +i , 5 -i
f(z) = (x -5 -i)(x -5 +i)



