Exercise 1415 Algorithmic Given are five observations for tw
{Exercise 14.15 (Algorithmic)}
Given are five observations for two variables, x and y.
The estimated regression equation for these data is = 1 + 2.6x.
Compute the coefficient of determination r2 (to 3 decimals).
Does this least squares line provide a good fit?
SelectYes, the least squares line provides a very good fitNo, the least squares line does not produce much of a fitItem 5
Compute the sample correlation coefficient (to 4 decimals).
| xi | 1 | 2 | 3 | 4 | 5 |
| yi | 4 | 7 | 7 | 11 | 15 |
Solution
xi
yi
y pre
SSE
SST
SSR
1
4
3.6
0.16
23.04
27.04
2
7
6.2
0.64
3.24
6.76
3
7
8.8
3.24
3.24
0
4
11
11.4
0.16
4.84
6.76
5
15
14
1
38.44
27.04
Total
5.2
72.8
67.6
MEAN Y
8.8
SSE
5.2
SST
72.8
SSR
67.6
Compute the coefficient of determination r2 (to 3 decimals).
=67.6/72.8 = 0.929
Does this least squares line provide a good fit?
SelectYes, the least squares line provides a very good fit
No, the least squares line does not produce much of a fit
Item 5
Compute the sample correlation coefficient (to 4 decimals).
r=sqrt(67.6/72.8) = 0.9636
( regression coefficient is positive.There fore correlation is positive)
The required r= 0.9636
| xi | yi | y pre | SSE | SST | SSR | |
| 1 | 4 | 3.6 | 0.16 | 23.04 | 27.04 | |
| 2 | 7 | 6.2 | 0.64 | 3.24 | 6.76 | |
| 3 | 7 | 8.8 | 3.24 | 3.24 | 0 | |
| 4 | 11 | 11.4 | 0.16 | 4.84 | 6.76 | |
| 5 | 15 | 14 | 1 | 38.44 | 27.04 | |
| Total | 5.2 | 72.8 | 67.6 | |||
| MEAN Y | 8.8 |


