A wire of 620 cm length and 13 g mass is suspended by a pair

A wire of 62.0 cm length and 13 g mass is suspended by a pair of flexible leads in a magnetic field of 0.440 T (Fig. 29-35). What are the magnitude and direction of the current required to remove the tension in the supporting leads??

Magnitude:

_________ A

Solution

the magnitude of the current is,

   i = mg/LB                   [Since, F = BiL, so mg = BiL]

     = 13*10^-3*9.8* / 0.62*0.44

     = 0.467 A

Direction: to the right