3 When a fraction of 57 is taken away from 57 what remains e

3. When a fraction of 57 is taken away from 57, what remains exceeds 57 by 4

Solution

Let the fraction taken away from 57 be x*57. Then 57 –x*57 = (2/3)*57+4 or, x*57 = 57-(2/3)*57-4 = 53-38 = 15. Therefore x = 15/57. Thus, when (15/57)of 57, i.e. 15 is taken away from 57, the remainder is 57-15 = 42. Also, (2/3) of 57 +4 = 38 +4 = 42. Hence the answer (15/57) is correct.