A train heads straight east at constant speed at 9am At noon

A train heads straight east at constant speed at 9am. At noon, a car heads straight east at twice the speed of the train. What time will it be when the car catches up to the train?

Solution

For this problem I drew a graph to help represent times and distance for each vehicle.
First, If the train is going 50mph for 3 hours (9-12) that would equal 150 miles reached. If the car is going twice as fast, in this case, 100 then at one o\'clock the car would have traveled 100 miles(add100mph); while the train would have traveled 200 miles(add50mph). By 2 o\'clock the car would have traveled 200, and the train 250 miles. By 3 o\'clock the car would reach 300 miles, and the train as well. So, they both would meet at 3pm.