Using the isothermal transformation diagram for an ironcarbo
Solution
A: After cooling and holding at 400°C for 500 s, the entire specimen has transformed to bainite.
Therefore, during the cooling to room temperature no additional transformations will occur. Hence, the
final microstructure consists of 100% bainite
B: Heating to 700°C for 20 h the specimen in part (a) will transform the coarse pearlite and
martensite to spheroidite.
C: After cooling to and holding at 665°C for 103s, approximately 100% of the specimen has transformed
to pearlite
D: During the rapid cooling to 350°C no transformations occur. At 350°C we start
timing again at zero time; while holding at 350°C for 150 s, approximately 100 percent of the remaining
unreacted 50% (or 25% of the original specimen) will transform to bainite. And upon cooling to room
temperature, the remaining 25% of the original specimen transforms to martensite. Hence, the final
microstructure consists of about 50% pearlite (medium), 25% bainite, and 25% martensite.
