For the given table of observed frequencies perform a test f
Solution
Doing an Expected Value Chart,
58.63570392 71.40783745 69.95645864
81.21044993 98.89985486 96.88969521
62.15384615 75.69230769 74.15384615
Using chi^2 = Sum[(O - E)^2/E],
chi^2 = 14.06859651
With df = (a - 1)(b - 1), where a and b are the number of categories of each variable,
a = 3
b = 3
df = 4
Thus, the critical value is
significance level = 0.01
chi^2(critical) = 13.27670414
Also, the p value is
P = 0.007079312
Thus, comparing chi^2 and chi^2(crit) [or, p and significance level], we REJECT THE NULL HYPOTHESIS. [OPTION B]
