A spring with a 2kg mass and a damping constant 1 can be hel

A spring with a 2-kg mass and a damping constant -1 can be held stretched 0.5 meters beyond its natural length by a force of 1.5 newtons. Suppose the spring is stretched 1 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value c^24mk? (I got -23 which is correct)

Find the position of the mass after t seconds. Your answer should be a function of the variable t with the general form c1e^(t)cos(t)+c2e^(t)sin(t)

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c1=    c2=

Solution