Evaluate integral12integral01 X exy dydx Evaluate integral0p

Evaluate: integral_-1^2integral_0^1 (X e^xy) dydx Evaluate: integral_0^pi integral_0^six(x) [1 + cos(x)]dy dx

Solution

R\' = R + Ra (Since R and the ammeter resistance are in series ) = 85.0 + 2.50 = 87.50 ohm

Req=R\' and Rv are in parallel so their equivalent resistance is = (RxRv)/(R+Rv)=70 ohm

Total resistance in the circuit = Req+Ro = 70+ 75 = 145 ohm

The current across Ro= 12/145 = 0.08275 A

i= Ammeter Reading

As the voltage across Voltmeter = voltage across R and ammeter

(0.08275-i)x(350)= i x (87.5)

i = 0.0662 A

a) Voltmeter Reading ,V\'= i x 87.5 = 5.79 V

b) Ammeter Reading = i = 0.0662 A

c) R\' =V\'/i = 87.5 ohm