Let AB be sets let fAB f A B and let S be an equivalence rel
Let A,B be sets, let f:AB f A B and let S be an equivalence relation on B. Let R be the relation on A given by xRy if, and only if f(x)Sf(y) x R y if, and only if f x S f y . Show that R is an equivalence relation on A.
Solution
1. Check reflexive property
Let x be any element in A
So we need to check if xRx
f(x)S f(x) because S is equivalence
Hence, xRx . HEnce, R is reflexive since x is arbitrary element in A
2. Check if R is symmetric
Let, xRy
Hence, f(x)Sf(y)
S is equivalence ehnce, S is symmetric hence, f(y)Sf(x)
Hence, yRx
Hence, R is symmetric
3. Check for transitive property
Let, xRy,yRz
Hence, f(x)Sf(y),f(y)Sf(z)
S is equivalence hence transitive so ,f(x)Sf(z)
Hence, xRz
Hence, R is transitive and hence equivalence relation on A
