Block B moves downward with a constant velocity of 610 mms D

Block B moves downward with a constant velocity of 610 mm/s. Determine: a. The velocity of block A b. The velocity of block C c. The velocity of portion D of the cable d. The relative velocity of portion D of the cable with respect to block B

Solution

a) 2vA = 3vB

vA = 3 x 610 /2 = 915 mm/s upward

b) vB = 2vC

vC = 610 /2 = 305 mm/s upward

c) vD = 3vB = 3 x 610 = 1830 mm/s downward

d) vDB = vD - vB = 1830 - (610) = 2440 mm/s downward