In Exercises 1527 you are asked to solve a trigonometric equ

In Exercises 15–27 you are asked to solve a trigonometric equation, either by finding all solutions, or only those in a specified interval.

b.26. Given the equation tan x = 1, find only the solutions that are in the interval [, 6]. Use exact values.

27. Given the equation tan x = 7, find only the solutions that are in the interval [, 6]. Round to nearest 0.01.

26 tan x = 1 in the [ , 6]

x = tan^-1(-1) = pi-pi/4 , 2pi-pi/4

= 3pi/4 +pi*n

x = -pi/4

n =0 ; x= 3pi/4

n=1 ; x= 7pi/4

n= 2 ; x= 11pi/4

n = 3 ; x= 15pi/4

n =4 \' x= 19pi/4

n = 5 ; x= 23pi/4

Solution ( -pi/4, 3pi/4, 7pi/4, 11pi/4, 15pi/4, 19pi/4 , 23pi/4 )

27. tanx = -7 interval [, 6]

x = tan^-1(-7) +pi*n

n=0 x = 2pi -tan^-1(7) = 4.85

n=1 ; x=7.996

n=2 ; x= 11.137

n =3 ; x= 14.279

n = 4; x= 17.421