8 A box of parts contains 8 good items and 2 defective items

8. A box of parts contains 8 good items and 2 defective items. If 2 are selected at random with

replacement, - that is, the first item is replaced before the second is drawn - find the

probability that the first is defective and the second is good.

Solution

Here,

P(good) = 8/10 = 0.8
P(defective) = 2/10 = 0.2

Thus,

P(defective then good) = P(defective) P(good) = 0.2*0.8 = 0.16 [answer]