M4i9 15 You Pathways lMathAS Assess e Chegg Study I Guided S

M4i9 #15

You Pathways lMathAS Assess e Chegg Study I Guided So × -> https://imathas.rationalreasoning.net/assessment/showtest.php?action-skip&to;=14 For quick access, place your bookmarks here on the bookmarks bar. Import bookmarks now... a @ Home > Murdock Precalc 013> Assessment Jeremee Hemphill M4 I9 Homework Due in 7 hours, 10 minutes. Due Wed 04/27/2016 11:59 pm Show Intro/Instructions Questions A rubber ball is dropped onto a hard surface from a height of 6 feet, and it bounces up and down. At each bounce it rises 85% of the height from which it fell. a. Find a formula for h(n), the height in inches reached by the ball on bounce Tn Q2[44] h(n) = * Preview Q4 [3/3] b. How high will the ball bounce on the 9th bounce? inches Preview c. On bounce the ball will rise no higher than an inch. (You can\'t have part of a bounce.) Q8[44] Preview Q 10 [1/1] Q 11 [3/3] C Q 12 (1/5) C Q13 (2/3) C Q 14 (0/3) C Q 15 (0/3) C Q 16 (0/3) Q17 (0/6) C Q 18 (0/4) Q19 [1/1] : 3 License Points possible Unlimited attempts Score on last attempt: 0. Score in gradebook: 0 Post this question to forum Submit Grade: 39/63 Print Version ) 4:49 PM 4/27/2016

Solution

Intial heoght h = 6feet

after 1st bounce = 6*0.85

after 2nd bounce = 6*(0.85)(0.85) = 8(0.85)^2

after nth bounce = 6*(0.85)^n

a) h(n) = 6(0.85)^n

b) after 9the bounce h(9) = 6(0.75)^9 =0.45 inches

c) h(n) = 1 = 6(0.75)^n

0.167 =0.75^n

take natural log on both sides:

ln(0.167) = n*ln(0.75)

n = 6.23 = 6 th bounce