s 20 points Suppose that there is a 085 probability that a r
Solution
8. Suppose that there is a 0.85 probability that a randomly selected adult knows what Twitter is.
a)
Note that the probability of x successes out of n trials is
P(n, x) = nCx p^x (1 - p)^(n - x)
where
n = number of trials = 4
p = the probability of a success = 0.85
x = the number of successes = 3
Thus, the probability is
P ( 3 ) = 0.368475 [ANSWER]
*****************
b)
Note that the probability of x successes out of n trials is
P(n, x) = nCx p^x (1 - p)^(n - x)
where
n = number of trials = 4
p = the probability of a success = 0.85
x = the number of successes = 0
Thus, the probability is
P ( 0 ) = 0.00050625
Note that the probability of x successes out of n trials is
P(n, x) = nCx p^x (1 - p)^(n - x)
where
n = number of trials = 4
p = the probability of a success = 0.85
x = the number of successes = 1
Thus, the probability is
P ( 1 ) = 0.011475
Thus,
P(0 or 1) = P(0) + P(1) = 0.00050625 + 0.011475 = 0.01198125 [ANSWER]
************************
c)
Note that the probability of x successes out of n trials is
P(n, x) = nCx p^x (1 - p)^(n - x)
where
n = number of trials = 30
p = the probability of a success = 0.85
x = the number of successes = 20
Thus, the probability is
P ( 20 ) = 0.006715271 [ANSWER]
*************************
d)
Note that P(at least x) = 1 - P(at most x - 1).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 30
p = the probability of a success = 0.85
x = our critical value of successes = 15
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 14 ) = 1.14474E-06
Thus, the probability of at least 15 successes is
P(at least 15 ) = 0.999998855 [ANSWER]
*******************************************
Hi! Please submit the next part as a separate question. That way we can continue helping you! Please indicate which parts are not yet solved when you submit. Thanks!

