The growth of a certain species in millions since 1980 close

The growth of a certain species (in millions) since 1980 closely fits the following exponential function where t is the number of years since

1980. Upper A(t)= 3300 e Superscript 0.0166 tA(t)=3300e0.0166t

a. The population of the species was about 3906 million in 1990. How closely does the function approximate this value?

b. Use the function to approximate the population of the species in 2000. (The actual population in 2000 was about

4709vmillion)

c. Estimate the population of the species in the year 2015.

Solution

A(t)= 3300 e(0.0166t)

a) A(t) = 3906 million , in 1990

t = 10 ; A(10) = 3300e^(0.0166*10) = 3300*1.18 = 3895.89

So, function closesly gives the value

b) In 2000 ; t = 20

A(20) = 3300e^(0.0166*20) = 3300*1.39 = 4599.38 million

c) In 2015 ; t = 35

A(35) = 3300e^(0.0166*35) = 3300*1.787 = 5899.82 million

The growth of a certain species (in millions) since 1980 closely fits the following exponential function where t is the number of years since 1980. Upper A(t)=

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