In a Frisbee throw the forearm undergoes 120 degrees of exte

In a Frisbee throw, the forearm undergoes 120 degrees of extension relative to the elbow. If the hand is located 0.28 meters from the elbow rotates, what is the linear distance the hand travels during the throw?

Solution

linear distance the hand travels = angluar distance in radians*radius

= (p/180)*120*0.28

= 0.586 mt