Let PA 039 PB 034 and PA B 004 a Are A and B independent
| Let P(A) = 0.39, P(B) = 0.34, and P(A ? B) = 0.04. |
| a. | Are A and B independent events? | ||||||||
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| b. | Are A and B mutually exclusive events? | ||||||||
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| c. | What is the probability that neither A nor B takes place? (Round your answer to 2 decimal places.) |
| Probability | |
| Let P(A) = 0.39, P(B) = 0.34, and P(A ? B) = 0.04. |
Solution
Two events A and B are independent events if P(A)*P(B)=P(A and B)
here (A and B)=.04 and P(A)*P(B)=.39*.34 =.1326
Thus it is not and independent event
No because P(A and B) is not equal to P(A/B)*P(B)
condition for mutually exclusive P(A and B) should not be equal to 0
here it is not equal to 0 therefore it is not mutually exclusive event option D
P(A or B) = P(A) + P(B) - P(A & B) = .39+.34-.04 = .69
P(neither A nor B) = 1 - P(A or B) = .31
