An ordinary sixsided die is rolled 12 times if X1 is the num

An ordinary six-sided die is rolled 12 times. if X1 is the number of 1`s, X2 is the number of 2`s, and so on, given the probability for each of the following events:

1. [X1=2, X2=3, X3=1, X4=0, X5=4, X6=2]

2.[X1=X2=X3=X4=X5=X6]

3.[X1=1,X2=2,X3=3,X4=4]

4. write an expression for the joint pdf of X1,X3, and X5.

Solution

x1 = 2

1/6 * 1/6 = 1 / 36

x2= 3

2 / 36

x3 = 1

1 / 36

x4

2 / 36

x5

4 / 12

x6

2 / 12

2)

1 / 12

for the other literals

I can gladly help you but you should post it in a new question