Suppose that n is an integer Show that the following three s
Suppose that n is an integer. Show that the following three statements are equivalent
3n + 4 is even.
n + 5 is odd.
n2 is even.
by showing (i) (ii) and (ii) (iii).
Solution
To show that all the 3 statements are eqivalent we need to prove or disprove all three statements simultaneously,
let n=even,
this means n=2k;
thus,
1) 3n+4=3x2k+4=2x3k+4=even => true
2) n+5= 2k+5= 2k+4+1 = even +1= odd =>true
3)n2 = (2k)2 =even=>true
=> it is equivalent
taking n=odd
this means n=2k+1
thus,
1) 3n+4=3x(2k+1)+4=2x3k+4+3= odd => false
2) n+5= 2k+1+5= 2k+6 = even =>false
3)n2 = (2k+1)2 = 4k2 +4k+1 = odd=>false
all the statements are false
=> it is equivalent
