Find all solutions of the equation in the interval 0 2 pi co
Find all solutions of the equation in the interval [0, 2 pi]. cos 2x+ cos x = -1 Write your answer in radians in terms of pi. If there is more than one solution, separate them with commas.
Solution
cos2x +cosx =-1 interval [ 0, 2pi )
use the formula: cos2x = 2cos^2x -1
2cos^2x - 1 +cosx = -1
2cos^2x +cosx =0
cosx( 2cosx +1) =0
cosx =0
x = pi/2 , 3pi/2
cosx = -1/2
x = pi-pi/3 , pi+pi/3 ( cos is -ve in IInd and IIIrd quadrant)
x = 2pi/3 , 4pi/3
Solution : x= pi/2 , 2pi/3, 3pi/2 , 4pi/3
![Find all solutions of the equation in the interval [0, 2 pi]. cos 2x+ cos x = -1 Write your answer in radians in terms of pi. If there is more than one solutio Find all solutions of the equation in the interval [0, 2 pi]. cos 2x+ cos x = -1 Write your answer in radians in terms of pi. If there is more than one solutio](/WebImages/12/find-all-solutions-of-the-equation-in-the-interval-0-2-pi-co-1010894-1761521832-0.webp)