Create a set of 5 positive numbers repeats allowed that have

Create a set of 5 positive numbers (repeats allowed) that have median 12 and mean 8. (Enter your answers as a comma-separated list.)

5 numbers we select such that median is 12.

Hence third number should be 12, if arranged in ascending order.

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Let us consider 2 numbers less than 12 say 8 and 9

The first 3 numbers are 8,9,12, x, y

As mean = 8 total = 40

Or 19+x+y =40

x+y =21

We cannot find numbers greater than 12 for x and y both.

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So change our assumption of first two numbers to 1 and 3.

Then 1+3+12+x+y=40

x+y =24

x =12, y =12

Thus the 5 numbers are

1,3,12,12,12

(Note: This is not the unique solution)