Becky traveled an average of 60 mph on a trip to St Louis On

Becky traveled an average of 60 mph on a trip to St. Louis. On her return trip, she took a more scenic route that was 2 hours longer and 30 miles farther and averaged 50 mph on the way back. How long did it take to Becky to travel to St. Louis?

Solution

To St. Louis DATA:
rate = 60 mph ; time = x hrs ; distance = rt = 60x miles
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From St. Louis DATA:
rate = 50 mph ; time = x + 2 hrs ; distance = rt = 50(x+2) miles
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Equation:
\"from distance\" - \"to distance\" = 30
50(x+2) - 60x = 30
50x + 100 - 60x = 30
-10x = -70
x = 7 hrs (time it took for her to go to St. Louis)