In the Bohr model the electron in H has a circular orbit For

In the Bohr model, the electron in H has a circular orbit. For an isolated atom, the only force on the electron is the strictly radial electrical force. Hence, the electron orbit must be in a plane. That is, it does not move over the surface of a sphere, but only along a single path around the sphere. Does this violates the uncertainty principle?

Please provide a well descripted answer. Thanks.
In the Bohr model, the electron in H has a circular orbit. For an isolated atom, the only force on the electron is the strictly radial electrical force. Hence, the electron orbit must be in a plane. That is, it does not move over the surface of a sphere, but only along a single path around the sphere. Does this violates the uncertainty principle?

Please provide a well descripted answer. Thanks.

Please provide a well descripted answer. Thanks.

Solution

In the Bohr atom model, momentum and positon are precisely defined quantites. This is direct violation of uncertainity principles.

Heisenberg uncertainity principle states that it is impossible to determine accurately the position and momentum of a electron. Relative to the Heisenberg Uncertainty principle, Bohr\'s Model is not consistent in it.

 In the Bohr model, the electron in H has a circular orbit. For an isolated atom, the only force on the electron is the strictly radial electrical force. Hence,

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