For a vibration system of single degree of freedom shown in
For a vibration system of single degree of freedom shown in the figure below, the cylinder 2 rolls without slipping, r_1 = r, r_2 = 1.5r, R = 2r, J_1 = 1/2 m_1 R^2, m_1 = 2m and m_0 = m_2 = m. By using kinetic energy equivalence, the equivalent mass of the system shown in the figure with respect to x is. 13/2 m 6m 11/2 m 5/2 m
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