Y is a uniform discrete RV over 1 2 3 X is dependent on y an

Y is a uniform discrete RV over {1, 2, 3}. X is dependent on y and spans 1 to y. So, if y = 3, X = {1, 2, 3}; if y = 2, X = {1, 2}, etc. Find P[X = 2]

Solution

probability of y=1 =>1/3

P(Y=2)=1/3

P(Y=3)=1/3

so X=2 occurs when Y=3 and 2

probability of X=2 in Y=3=> 1/3*1/3=1/9

P(X=2) when Y=2=> 1/3*1/2=1/6

P(X=2)= 1/9+1/6 = 5/18

 Y is a uniform discrete RV over {1, 2, 3}. X is dependent on y and spans 1 to y. So, if y = 3, X = {1, 2, 3}; if y = 2, X = {1, 2}, etc. Find P[X = 2]Solutionp

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