x 32 3x2 5x 12SolutionWe have x 32 3x2 5x 12 or x2

(x - 3)^2 + 3x^2 - 5x = 12

Solution

We have ( x - 3)2 + 3x2 - 5x = 12 or, x2 - 6x + 9 + 3x2 - 5x = 12 or, 4x2 - 11x - 3 = 0 or, 4x2 - 12x + x - 3 = 0 or, 4x(x -3) + 1 (x -3 ) = 0 or, ( x - 3)( 4x + 1) = 0 . Therefore, either x - 3 = 0 which means that x = 3 or, 4x + 1 = 0 which means that x = - 1/4. Thus, the answer is that either x = 3 or, x = -1/4. We can verify this by substituting these values of x in the original equation.

 (x - 3)^2 + 3x^2 - 5x = 12SolutionWe have ( x - 3)2 + 3x2 - 5x = 12 or, x2 - 6x + 9 + 3x2 - 5x = 12 or, 4x2 - 11x - 3 = 0 or, 4x2 - 12x + x - 3 = 0 or, 4x(x -3

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