618 The random variable X is normally distributed with mean

6.18 The random variable X is normally distributed with mean Mu = 50 and Sigma=10. Find the following probabilities:

Solution

1) P(Z < (66-50)/10) = P(Z<1.6) = 0.9453

2) P(Z < (56-50)/10) = P(Z<0.6) = 0.7257

3) P( (43-50)/10) < Z < (63-50)/10) = P(-0.7 < Z<1.3 ) = 0.9032 - 0.2420 = 0.6612

4) P( (37-50)/10) < Z < (46-50)/10) = P(-1.3 < Z<-0.6 ) = 0.2743 - 0.0968 = 0.1775

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