The specific volume in m3kg of water at 200 kPa and 60 C is

The specific volume in m^3/kg of water at 200 kPa and 60 C is equal to The specific internal energy in kj/kg of water at 200 kPa and 60 C is equal to: The specific enthalpy in kJ/kg of water at 200 kPa and 60 C is equal to:

Solution

As per steam table

1. Specific volume 1.0170×10^-3 m3/kg

2. Specific internal energy 250.4748 kj/kg

3. Specific enthalpy 250.6782kj/kg