How do you factor x23x2 I need to find the roots of the equa

How do you factor (-x^2-3x-2) I need to find the roots of the equation using this trinomial. I know there are 2 imaginary roots but dont know how to show work for it. If someone could please help Id really appreicate it. Thanks.

(-x^2-3x-2)

find the roots : -x^2 -3x -2 =0

factorise the equation : -x^2-2x -x -2 =0

-x( x+2) -1(x +2) =0

(-x -1) (x +2) =0

x = -1 ; x =-2

So, (-x^2-3x-2) = (x+2)(-x -1)

How do you factor (-x^2-3x-2) I need to find the roots of the equation using this trinomial. I know there are 2 imaginary roots but dont know how to show work f

How do you factor x23x2 I need to find the roots of the equa

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